Possible Genotypes of parents~
Genotypes of parents could be as follows:
1. One Parent with the disease, one heterozygous, Two heterozygous for the trait, Two homozygous recessive for the trait.
Possible genotypes of parents include:
c=Cystic Fibrosis trait
+ = paired with
cc + Cc
Cc + Cc
cc + cc
CC + cc
1. One Parent with the disease, one heterozygous, Two heterozygous for the trait, Two homozygous recessive for the trait.
Possible genotypes of parents include:
c=Cystic Fibrosis trait
+ = paired with
cc + Cc
Cc + Cc
cc + cc
CC + cc
Percentages with Disease/Trait~
Approximately 2,500 babies in the U.S. are born with Cystic Fibrosis evry year. More than 10 million Americans carry the trait, and could pass it on, but dont even know it.
Passing on of the Gene~
Passing of the CF gene has to do with the parents genotypes. The genotype options are listed above under possible genotypes of parents. The percentages are as follows with the genotypes above:
Cc + cc = 75 % chance of child with disease, 25% carrier, 0% normal.
Cc +Cc = 25% chance of child with disease, 50% carrier, 25% normal.
cc + cc = 100% chance of child with disease.
CC + cc = 100% chance of child carrier.
You can figure out the above percentages by using the genotypes in punnett squares as shown to the right.
Cc + cc = 75 % chance of child with disease, 25% carrier, 0% normal.
Cc +Cc = 25% chance of child with disease, 50% carrier, 25% normal.
cc + cc = 100% chance of child with disease.
CC + cc = 100% chance of child carrier.
You can figure out the above percentages by using the genotypes in punnett squares as shown to the right.